# The sum of 3 consecutive integral numbers is 117. What are the numbers?

##### 1 Answer

May 24, 2016

#### Explanation:

If the second of the three numbers is

#117 = (n-1)+n+(n+1) = 3n#

Dividing both ends by

#n = 117/3=39#

So the three numbers are:

#38, 39, 40#